我的问题的代码,请问为何发送和接收指示灯同时闪烁?谢
#includereg52.h
int a,b=0;
unsigned int c;
void main()
{
P3=0x2B;
c=50000;
P1=0x14;
while(c--);
c=50000;
P3=0xd4;
P1=0x04;
while(c--);
c=50000;
P3=0x2B;
P1=0x5d;
while(c--);
c=50000;
P3=0xd4;
P1=0x24;
while(c--);
c=50000;
P3=0x2B;
P1=0x34;
while(c--);
c=50000;
P3=0xd4;
P1=0x9C;
while(c--);
c=50000;
P3=0x2B;
P1=0x54;
while(c--);
c=50000;
P3=0xd4;
P1=0x46;
while(c--);
c=50000;
P3=0x2B;
P1=0xDD;
while(c--);
c=50000;
P3=0xd4;
P1=0x05;
while(c--);

}

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2008-11-4 11:41:16 [yorton]〖119.129.197.49〗：waiting for massage!

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2008-11-4 13:22:20 [51dz]〖58.61.55.214〗：发送接收灯就是P3.0和P3.1的引脚状态变化指示,你的代码有更改P3口的状态,LED自然就会闪了.